- A test piece has diameter 31,1 mm and reference length 189 mm. Imagine that a force of 266 mm lengthen the reference length by 1,12 mm determine the modulus of elasticity. Use G: 18Gpa. σ: 525,25Mpa.
Solution:
Average normal tension
σ = P/A
σ = 266000/((π/4)*(0,0311)²)
σ = 350,16 Mpa
Average normal strain
ε = δ/L
ε = 1,12/189
ε = 0,005926 mm/mm
Modulus of elasticity
E = σ/ε
E = 59,09 Gpa
- ISBN:
- 1230005904266
- 1230005904266
-
Category:
- Higher & further education
- Format:
- Epub (Kobo), Epub (Adobe)
- Publication Date:
-
04-11-2022
- Language:
- English
- Publisher:
- Edenilson Brandl
This item is delivered digitally
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